@tbkprogrammer

### *Output:*
`True`

1. `x` is `(lambda: 5)`, a function returning `5`.  
2. `y` is `lambda f: f()`, which calls `f`.  
3. *First part:* `x == y(x)` checks if `(lambda: 5)` is equal to `y((lambda: 5))`.  
   - `y((lambda: 5))` calls `(lambda: 5)`, returning `5`. So, `x != y(x)`.  
4. *Second part:* `y(x) == x` checks if `y((lambda: 5)) == (lambda: 5)`.  
   - `y((lambda: 5))` evaluates to `5`, which isn't equal to the function `x`.  
5. Both comparisons result in `False`, so `(False == False)` returns `True`.