Easiest ayt question
Everytime i see this type of questions i remember Pythagorean theorem 😂
First construct the 7-24-25 triangle by the Pythagorean Theorem. Denote by R the radius of the circle, R=sqrt(625-x²). By opposite angles supplementary, the quadrilateral with sides length 24,7,R,x is a cyclic quadrilateral. Then, by the Ptolemy's Theorem, 25*sqrt(625-x²)=7*sqrt(625-x²)+24x Hence x=15
Special right triangle 7-24-25 (2R)²=24²+(7+25)² --> R= 20cm x² = 25²-R² --> x= 15cm
in turkey this is just simple guy
I started to see Pythagoras theorem in my dreams😂😂
Thanks 🎉
A normal question in turkey exams
In my younger years I was very good at math, now I'm turning 60 and haven't used math much so I couldn't solve this. When I saw the solution I was a bit embarrassed. I have to re study this.
24^2+7^2=y^2+x^2 x^2=y^2+7^2-2*7*y*sqrt(1-((24/2)/y)^2) 625=y^2+x^2 x^2=y^2+7^2-2*7*y*sqrt(1-(12/y)^2) x^2=625-x^2+7^2-2*7*sqrt(625-x^2)*sqrt(1-144/(625-x^2)) answer : x=15
So goooooddddd
The thing I loved the most is that all the values we encountered in the question are whole numbers. ❤️
You missed using 3,4,5 triangle at the end (15,20,25) and earlier in the 24, 32, 40 one
The hardest part of this question is calculating whats square of 24 plus square of 32 without using pen and paper, in my mind. It comes pretty funny for turkish students that you think the question is hard.
3:39 SO GOOD
Set r² equations equal then 25²-x²=24²÷2²+32²÷2² so x²=25²-16²-12² x²=(25+16)(25-16)-12•12 x²=41•-9-12•9-12•3 x²=41•9-12•9-9•3-3•3 x²=(41-12-3-1)•9 x²=25•9 x=5•3 x=15 whatever units.
since there 4 points are on same circle, (in that picture, say AB=24,BC=7,CD=x, DA=radius) angle(BCA)=angle(BDA) so cos(BDA)=24/25 since AD=BD, you can get AD=20 very easily. noticing AC=25, you can know that x=15 that's how i solved this...
Wait till turkish people see greek exams
My solution: First, the four vertices of the square are called A, B, C, and D in clockwise order from the top. Then, BD = 25 (pythagorean). ∠BCD is 90°, so □ABCD is on a circle. (∠DAB + ∠BCD = 180°) As □ABCD is on a circle, AB×CD + BC×DA = AC×BD. then just substitute (radius of the fan = r) 7×r + x×24 = r×25 24x = 18r r = 4/3 x Now △BCD is a right triangle with 25, x, 4/3 x Use pythagorean, then x is 15.
@eylulkorkmaz5776