They will never form a square of any size except for the original one, as they clearly can’t form a smaller square and if they could form a bigger one then they would also be able to form a smaller one
I did come to the conclusion that they couldn't form the larger square, although I didn't understand that diagonal jumps would be allowed, not that it seems to have made a difference
This was such a satisfying one to solve.
A different explanation: the parity of each coordinate of each spider is invariant. But it is different for the smaller and the larger squares.
If you allow simultaneous jumps (where they jump of where the other spider is at the instant they begin the jump, then that can make a larger square (albeit rotated relative to the original, and some factor larger that I cba to calculate). This looser version works because it breaks the reversibility of each move, which is a necessary feature for the version presented
Lovely proof, great visuals
You should have told they can move diagonally
Вопрос можно иначе поставить: можно ли получить квадрат со стороной в два раза меньше ?
I figured this out using a chessboard
You never said they could jump diagonally, or over multiple spiders.
my answer was right!! should have spent this shot in a casino :,)
The logic that they couldn’t have gotten from smaller square to the bigger square because they can’t go from bigger to smaller is not a good argument imo. How would you disprove the hypothesis that they can go from smaller to bigger but not from bigger to smaller.
Kinda reminds me of my math teacher
This is wrong "They always jump the same distance and only over each other once" *Proceeds to jump across the entire map, and over two spiders*
I didn't understand this video. am I stupid?
spider
Im so intelligent 🤓
AHHHHHHHHHHH
Am I early?
@aristotlekaporis7337