@varisharahman6790
Simplified ans--- (Infinity,-4] union [4, infinity)
@jasondominick5230
Fun fact: f(x) represents the upper half of a hyperbola. To see this, note that the equation for a hyperbola has the standard form (x/a)^2 - (y/b)^2 = 1. In this case, a=b=4. Substituting this in and solving for y gives that y = +/- sqrt(x^2 - 16). To obtain a function of x (as this result is a relation but not a function), you simply choose either the positive or negative square root.
@useerone870
ok but why did we flipped sign for negative value ?
@leadyboi334
domain expansion
@gonzalotapia1250
Domain is [-infinity,-4], [4,+infinity]
@DevDroidios
(-4,-infinity)u(+4,,+infinity)
@davidvernon3119
There’s no problem mathematically to have a function over the imaginary numbers. In fact it is required in many engineering disciplines
@nintendoswitchfan4953
You are not finding the domain but rather the domain when the range is the real numbers
@natnaelalem848
but 4 is a working number , b/c when you square 4 and decrease 16 it gives you 0, and zero of square root is zero so it should be D=R / (-4,4)
@peaklongshot7205
So (-inf,-4]U[4,inf)
@SakinaBaTool-r9h
Plz also solve for range ... Plz
@MrRight022
A better solution would be taking whole x²-16 greater than or equal to zero then use wavy curve method to find the solution
@leprechaunswag270
How to you determine the inequalities signs? Like why x>4 not 4>x ?
@Viva_Cynefin
Of course I had to get it now after the test
@boruru9987
Wouldn't it be better to say x²>16 |x|>4 x>4 or x<-4 I know there should be a "greater than or equal to" instead of "greater than" symbol but I don know how to write that.
@anonymosly
R - (-4,4)
@marwasnetworkofartandtechn8907
Thnkuuuu
@justinpiyobot
Silly questions 😁 for my class
@4thsanninn
what if you have this: x times square root of: x^2 - 16
@4thsanninn