@4thsanninn

crazy how this is exactly what i was looking for

@varisharahman6790

Simplified ans---
(Infinity,-4] union [4, infinity)

@jasondominick5230

Fun fact: f(x) represents the upper half of a hyperbola. To see this, note that the equation for a hyperbola has the standard form (x/a)^2 - (y/b)^2 = 1. In this case, a=b=4. Substituting this in and solving for y gives that y = +/- sqrt(x^2 - 16). To obtain a function of x (as this result is a relation but not a function), you simply choose either the positive or negative square root.

@useerone870

ok but why did we flipped sign for negative value ?

@leadyboi334

domain expansion

@gonzalotapia1250

Domain is [-infinity,-4], [4,+infinity]

@DevDroidios

(-4,-infinity)u(+4,,+infinity)

@davidvernon3119

There’s no problem mathematically to have a function over the imaginary numbers. In fact it is required in many engineering disciplines

@nintendoswitchfan4953

You are not finding the domain but rather the domain when the range is the real numbers

@natnaelalem848

but 4 is a working number , b/c when you square 4 and decrease 16 it gives you 0, and zero of square root is zero so it should be D=R / (-4,4)

@peaklongshot7205

So (-inf,-4]U[4,inf)

@SakinaBaTool-r9h

Plz also solve for range ... Plz

@MrRight022

A better solution would be taking whole x²-16 greater than or equal to zero then use wavy curve method to find the solution

@leprechaunswag270

How to you determine the inequalities signs? Like why x>4 not 4>x ?

@Viva_Cynefin

Of course I had to get it now after the test

@boruru9987

Wouldn't it be better to say
x²>16
|x|>4
x>4 or x<-4

I know there should be a "greater than or equal to" instead of "greater than" symbol but I don know how to write that.

@anonymosly

R - (-4,4)

@justinpiyobot

Silly questions 😁 for my class

@4thsanninn

what if you have this: x times square root of: x^2 - 16