True @ Annwesha Dutta it should be numDiff(2)=.../(2*h(2))

and so the answer comes out to [0.107666      19.3798]  and not  [0.107666      38.7596]

typo at 19:34 It will be numDiff(2)=.../(2*h(2))

In the end also it is incorrect as you have taken the original equation into consideration rather than taking two equation for partial derivatives

I think cos in place of sin

Is this course enough for learning matlab?