@wish_i_had_a_river
All I see is criticism in these comments. You guys this channel isn’t for those of you who already know this. It’s for people who are just starting out and want the basic concepts. Leave him alone. Thank you for that videos I appreciate them greatly (I am currently in Calc 1) and these videos help keep my algebra skills sharp!
@Serious_SL_
out of all the crap that goes through YT shorts, this is one of the few channels that i'm happy to stumble upon. It's fun to refresh your memory of some of the basic math that any one should know. And the format is perfect: straight to the point , no useless words or intro. Perfect.
@htetaung04
I believe you have to state that the function is undefined for y = 1/5 which is the value that makes the denominator of the original function go to 0
@samerbader___xd7923
I've had a huge problem solving the inverse function, but your explanation has made it much easier. THANK YOU!
@popcornparker5390
You're a great teacher. Thank you
@Angel-x5b8s
I hate math but I can't stop watching this over and over again because of the sound of the chalk. It's satisfying for some reason😭 It was like an asm✨
@zahranf.a.9864
When you have f(x)=(ax+b)/(cx+d), the invers of that function is always f-¹(x)=(-dx+b)/(cx-a). In this function, a=2, b=3, c=-5, d=1 (remember that a and c are always the coef of x). So just switch a and d and make them negative, or if it already negative, make it positive.
@leeeezz
ur black board is so smooth, I like it
@reefu
I feel like this method can lead to confusion in students, because it can lead to a fundamental misunderstanding of what an inverse function is, especially when the variable names have a meaning attached. For example, say I have a velocity function with respect to time, and I want to solve for time, but I phrase the question as finding the inverse function, swapping the variable letters would make no sense in this case. Instead, just solve for time as a function of velocity, or in this more abstract example, solve for x as a function of y.
@isaacaguilar5642
Lets say we have a “y” be a function of x so we can say that y = f(x) If we swap x and y, we see x = f(y) and solving for y, we get y = f^-1(x) and now y is the inverse function. This is why swapping x and y can solving for y works, for anybody confused.
@Notification099
Thank you extremely much Please don't give up I swear your channel is great
@fatemehalmasi6153
Nice . You can also inverse the two processes. First solve for X and then substitute X with Y. Your work reminds me of my enjoyable life during highschool
@JeremyCoppin
Wish I had this 30 years ago.
@popcornparker5390
I appreciated the slight pause
@itrstt66
i love your notation!
@ryanmahadeo3132
Thats a nice short long solved, professor.
@danuttall
At the end, I would have switch the signs on all terms in the numerator and denominator. f(x) = (2x+3)/(1-5x) x = (2y+3)/(1-5y) x(1-5y) = 2y+3 x-5xy = 2y+3 -5xy - 2y = -x + 3 Switch the signs on all terms. 5xy + 2y = x - 3 Now factor out y. y(5x+2) = x - 3 y = (x-3)/(5x+2) Then back to functional form: f^(-1) = (x-3)/(5x+2)
@eannacoleman957
I would recommend getting rid of the negative by factorising out that -1 in the denominator on the right
@lawlaw8530
I once "cancelled out" everything like that and every answer I put is wrong. Lmao.
@mikeblaszczak5346