when it comes to choosing your "u" you can use "LIATE" to know what to prioritize L-ogarithmic function I-nverse trig function A-lgebraic function T-rigonometric function E-xponential function
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I'm at one of the best universities in my country and this guy still does a better job actually explaining concepts in a timely manner than any prof I've had.
0:08 ex times e to the ex (x*e^x) power. 1:55 ex times sine of ex (xsin(x)) 3:30 ex squared times natural log of ex (x²ln(x)) 6:05 natural log of ex (ln(x)) 7:43 ex squared times sine of x (x²•sin[x]) 11:30 ex squared times e to the ex (x²•e^x) 14:55 the square of the natural log of ex (ln[x])² 17:26 natural log of ex to the seventh power (ln[x⁷]) 18:39 the product of e to the ex and sin of ex ([e^x]•sin[x])
Students around the globe are behind you. Best teacher ever.
Divided By Colleges, United By This Guy 😂
so disrespectful of those tutoring company ads to play on this video and say stuff like 'are the videos from 2006 really helping'... when this video is, indeed, helping a lot.
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You’re carrying my Calc 2 grade rn. Your such a godsend I swear. You’re the reason I passed Calc 1 at Uni. I owe you big time!
I had year gap because of the pandemic and had forgotten integration. My high school math teacher was also not so good at explaining stuffs. THe way you explain has made me much better at integration in just 2 days. Thank you very much sir. Keep up the good work.
In math class my teacher used to treat me like a slow learner but since I came to know you, I shone and I also explain to my fellows. Thankyou sir.
You've saved my life more times than I can count. Much of my college education is owed to you, thanks!
The epiphany at 21:00 truly hit different after thinking about how to solve that integral for so long. All hail the organic chem tutor.
Lol I have to confess that you're the reason I attended classes sparingly back in my varsity days 😂. I used to watch your videos religiously. Now I'm a lecturer and I still watch them. Thanks a million times 🎉
For the problem at 22:30, you could also use u-substitution to make u = lnx and du = l/xdx. Then, the integral would just be u squared du and the antiderivative would be (u cubed over 3) + C. By back substitution, you would get (lnx cubed over 3) plus C. This is just a quicker way to do the problem for time constraints on a test.
Thank you so much for all the good work. You're indeed a mentor. You've helped me a lot so far with my Engineering course. Am in year 3 at the moment, two more years to go. Please keep it up
I’ve learned more from this guy then online school
im in a top3 college in my country studying computer science and I gotta say that without u I wouldn't be here nor would be able to make progress on calc classes
@TheOrganicChemistryTutor