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Comparing Two Lists for Order: A Python Guide

Discover how to compare the order of two lists in Python and efficiently determine if they match a base list's sequence. Learn coding techniques step-by-step!
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This video is based on the question https://stackoverflow.com/q/70242779/ asked by the user 'Jagadeeshkumar Viswanathan' ( https://stackoverflow.com/u/16749280/ ) and on the answer https://stackoverflow.com/a/70242913/ provided by the user 'Алексей Р' ( https://stackoverflow.com/u/15035314/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.

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Comparing Two Lists for Order in Python

When working with lists in Python, you may often need to ensure that one list maintains the same order as another. This task is especially important when validating data against a predefined sequence. In this guide, we will discuss how to compare two lists and check if the items in one list appear in the same sequence in a base list. We will break down the problem and illustrate a clear solution using a Python function.

The Problem

Suppose you have a main list, l, which contains several integers:

[[See Video to Reveal this Text or Code Snippet]]

You also have two other lists, l1 and l2, that you want to compare against l:

[[See Video to Reveal this Text or Code Snippet]]

The goal is to check if the items in l1 and l2 follow the same order as they appear in l. If l1 maintains the sequence, the result should be "PASS"; if l2 does not, the result should be "FAIL".

For l1: The sequence is valid, so the result is "PASS".

For l2: The sequence is invalid, so the result is "FAIL".

The Solution

To tackle this problem, we can create a function called compare that will take two parameters: the list to be tested (tested) and the base list (base). The function will determine whether the order of items in tested matches the order in base. Here's how you can implement this:

Step-by-Step Implementation

Create the Compare Function
We will use list comprehension to get the indexes of the items in the tested list from the base list.

[[See Video to Reveal this Text or Code Snippet]]

How It Works:

Finding Indexes: The line [base.index(t) for t in tested] builds a list of indexes for each item in tested based on their positions in base. For example, for l1, this will yield [1, 4] since 2 is at index 1 and 5 is at index 4 in l.

Comparison: We then check if these indexes are sorted. If they are sorted, it means the order is preserved, and we can return "PASS". If not, we return "FAIL".

Running the Function
You can test this function using the lists l1 and l2 like so:

[[See Video to Reveal this Text or Code Snippet]]

Conclusion

In summary, comparing the order of items between two lists in Python is straightforward once you know how to capture and evaluate the index positions. The compare function we developed efficiently checks if the items in a secondary list maintain the order defined by a main list. This method can be helpful in various applications, from data validation to algorithm development.

Feel free to implement this code in your projects and adapt it to suit your requirements. Happy coding!

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