Problem Link:
https://leetcode.com/problems/find-element...
Problem Statement:
Given a binary tree with the following rules:
root.val == 0
For any treeNode:
If treeNode.val has a value x and treeNode.left != null, then treeNode.left.val == 2 * x + 1
If treeNode.val has a value x and treeNode.right != null, then treeNode.right.val == 2 * x + 2
Now the binary tree is contaminated, which means all treeNode.val have been changed to -1.
Implement the FindElements class:
FindElements(TreeNode* root) Initializes the object with a contaminated binary tree and recovers it.
bool find(int target) Returns true if the target value exists in the recovered binary tree.
#leetcode #leetcodedailychallenge #dsa #java
コメント